T(a)=a^2-3a+12

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Solution for T(a)=a^2-3a+12 equation: 



(T)=T^2-3T+12

We move all terms to the left:

(T)-(T^2-3T+12)=0

We get rid of parentheses

-T^2+T+3T-12=0

We add all the numbers together, and all the variables

-1T^2+4T-12=0

a = -1; b = 4; c = -12;
Δ = b2-4ac
Δ = 42-4·(-1)·(-12)
Δ = -32
Delta is less than zero, so there is no solution for the equation

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